# Dragon egg plea to the DEV team

**URL:** <https://community.gemsofwar.com/t/dragon-egg-plea-to-the-dev-team/81210>\
**Category:** Uncategorized\
**Created:** [September 5, 2023, 5:55pm UTC](https://community.gemsofwar.com/t/dragon-egg-plea-to-the-dev-team/81210 "2023-09-05T17:55:00Z")\
**Posts on this page:** 1\
**Showing post:** 7

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**Author:** ![canadademon](https://avatars.discourse-cdn.com/v4/letter/c/e9bcb4/32.png) [@canadademon](https://community.gemsofwar.com/u/canadademon)\
**Post date:** [September 6, 2023, 1:51am UTC](https://community.gemsofwar.com/t/dragon-egg-plea-to-the-dev-team/81210/7 "2023-09-06T01:51:29Z")

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32 is about right, according to this prob chart

> [@More dragon egg issues](https://community.gemsofwar.com/t/more-dragon-egg-issues/78755/18):
>
> After pulling yet another dupe today, I realized that I was overcomplicating this problem. If I have X out of 6 dragons after Y pulls, the probability of me getting a new one is (6-X)/6. This is more easily written as a recursive function. Let P(x,y) be the probability of having x dragons after y pulls. Obviously P(1,1) = 1, as a base. Let’s say I have 4 dragons after 7 pulls. After 8, I have a 2/6 chance of getting 5, 4/6 of remaining at 4. (x,y) has a (x/6) chance to become (x,y+1), (6-x)/6 …

I’m waiting until I can craft 36 at once myself, as it’s the first 99% chance to get them all. OP’s 27 is only 96%.

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_[View the full topic](https://community.gemsofwar.com/t/dragon-egg-plea-to-the-dev-team/81210)._
